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cho s nguyn dng m=2, mt s nguyn dng n c gi l m-tt nu vs mi s nguyn dng a, (a;n)=1 ta c n| a^m – 1. cho s_ nguyên d__ng m>=2, m_t s_ nguyên d__ng n ___c g_i là m-t_t n_u vs m_i s_ nguyên d__ng a, (a;n)=1 ta có n| a^m – 1. ch_ng minh m_i s_ m-t_t không v__t quá 4m(2^n […]

cho s nguyn dng m=2, mt s nguyn dng n c gi l m-tt nu vs mi s nguyn dng a, (a;n)=1 ta c n| a^m – 1. cho s_ nguyên d__ng m>=2, m_t s_ nguyên d__ng n ___c g_i là m-t_t n_u vs m_i s_ nguyên d__ng a, (a;n)=1 ta có n| a^m – 1. ch_ng minh m_i s_ m-t_t không v__t quá 4m(2^n […]

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